The sum of all real ⁿ such that
(2ⁿ-4)³+ (4ⁿ - 2)³ = (4ⁿ + 2ⁿ-6)³
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Step-by-Step Explanation:
(2ⁿ⁺⁴ - 2.2ⁿ ) /( 2.2ⁿ⁺³) + 1/8
= (2ⁿ.2⁴ - 2.2ⁿ) / (2ⁿ 2⁴) + 1/8
Taking 2ⁿ common,
= [ 2ⁿ ( 16 - 2 ) / 2ⁿ 2⁴ ] + 1/8
Eliminating in the equation 2ⁿ,
We have,
= 14/16 + 1/8 = 7/8 + 1/8 = 1
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