Question

the sum of any two sides of triangle is greater than third Side

Answer 1

Answer:

$yes \\ your \\ are \\ correct$

Answer 2

$\Large{\textbf{\underline{\underline{According\:to\:the\:Question}}}}$

Given,

∆QWE

To Prove = QW + QE > WE

QW + WE > QE

Also,

WE + QE > QW

Construction :-

Produce side WQ to point S such that QE = QS

Now,

Join ES

Proof :-

In ∆QES,

QE = QS (Construction)

∠2 = ∠1 (Angle opposite to equal sides)

(∠2 + ∠3) > ∠1

∠WES > ∠1

Now in ∆WES

WS > WE (Side opposite to larger angle of ∆QWE) .... (1)

But,

WS = WQ + QS

= QW + QE

From (1) and (2)

QW + QE > WE

Similarly,

QW + WE > QE

Also,

WE + QE > QW