Question

The sum of digits of a number is 12. If both are interchanged, then the newly formed number is 36, more than the original number. What is the original number?​

O_N_L_Y. G​

Answer 1

BRAINLIEST ANSWER

Let the unit digit=X

Tens digit=12-X

The number=10(12-X)+X

The number after reversal=10(X)+12-X

The equation

10(12-X)+X-36 =10X+12-X

120–10X+X-36=10X+12-X

-10X+X-10X+X=12–120–36

-18X=-144

18X=144

X=144/18

X=8x

X=unit digit=8

Tens digit=12–8=4

The number=10(4)+8=48

Reverse number=84

84 is 36 more than 48

So the desired number is 48

Answer 2

Answer:

let's see..

let's digit be x and y

original number be 10x +y

then,

x+y= 12................1)

10x+y +36= 10y+x

9x-9y=-36...............2)

then

multiply eqn 1 by 9 we get,

9x+9y=108..............3)

solving eqn 2 and 3 by eliminating methods

9x-9y=-36

9x+9y=108

18x=72

x=4

putting the value in eq 1)

4+y= 12

y=8..

now original number =10x +y

= 10×4+8

=48