Question

the sum of digits of a two digit number is 10 .if 18 be subtrared from it the digits in the resuting number will be equal the number is

Answer 1

x = 10's digit of a two digit number(Let)

 y = units digit(Let)

n=Resulting equal digits(Let)

Condition 1-the sum of a two digit number is 10

x + y = 10

further simplifying

y = (10-x)

 Condition 2-if 18 be subtracted from it the digits in the resulting number will be equal

10x + y - 18 = 10n + n

10x + y = 11n+ 18

Substitutituting values found above

10x + (10-x) = 11n + 18

10x - x = 11n + 18 - 10

9x = 11n+ 8

If we solve it we will found the values as - x = 7, y = 3, z = 5 and finally we can say the no. is 73