the Sum of digits of a two digit number is 12.if the new number formed by reversing the digit is greater than the original number by 54,find the original number
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let no be xy
x+ y= 12
reverse yx
yx = xy +54
10 y + x= 10 x +y +54
9( y-x) = 54
y- x = 6
also x+ y = 12
add
2y = 18
y= 9
x= y-6 = 3
So 39
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