The sum of digits of a two-digit number is 8. If 36 is added to this number, the digits are
reversed. Find the number.
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Answer:
Let us assume x and y are the two digits of the number
Therefore, two-digit number is = 10x + y and the reversed number is 10y + x
Given:
x + y = 8
x = 8 – y ....... (1)
Also given:
10x + y + 36 = 10y + x
9y – 9x = 36
y – x = 4 ........(2)
Substitute the value of x from eqn (1) in eqn (2)
y – (8 – y) = 4
2y – 8 = 4
2y = 12
y = 6
Therefore, x = 8 – y = 8 – 6 = 2
Therefore, two-digit number
=10x + y = (10 × 2) + 6 = 26
and the reversed number
= 10y + x = (10 × 6) + 2 = 62
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