The sum of first n terms of an AP is given by Sn=2n^2+3n.find the 16 term of the AP
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Sn=2n^2 + 3n
S1=T1= 2(1)^2 + 3(1)
=5
S2=2(2)^2+3(2)
=14
T2= S2- S1
=9
AP: 5,9,13...
a=5, d=(9-5)=4
T16= a+(n-1)d
= 5+ 15(4)
=65
S1=T1= 2(1)^2 + 3(1)
=5
S2=2(2)^2+3(2)
=14
T2= S2- S1
=9
AP: 5,9,13...
a=5, d=(9-5)=4
T16= a+(n-1)d
= 5+ 15(4)
=65
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