Question

The sum of four consecutive integers is 266.what are the integers?
Give me solved the sum

Answer 1

let consecutive numbers be x, x+1,x+2,x+3

Answer 2

Let first number be x

Second number be x+1

Third number be x+2

Forth number be x+3

So, x+(x+1)+(x+2)+(x+3)=266

4x+6=266

4x=266-6

4x=260

x=260/4

x=65

So, first number=65

Second number =x+1=66

Third number=x+2=67

Forth number =x+3=68