Question

The sum of four consecutive multiples of 4 is 120...... Find these multiples.....

Answer 1

Let the smallest multiple be x
so 2nd no.= x+4
3rd no.=x+8
4th no.= x+12
According to question
(x)+(x+4)+(x+8)+(x+12)= 120
4x+24=120
x=120-24/4
x=96/4
x=24
Therefore the multiples are 24,28,32,36

Answer 2

40+40+40+40=120so 40 is the factor