The sum of four numbers in a.p is 24 and square of there product is 729. Find the numbers
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suppose the numbers are (a-3d), ( a - d), (a+d),(a+3d)
wkt sum s= n/2{2(a - 3d)+(n - 1) * 2d}
here
s= 24 and n=4
therefore a= 6
substituting a=6 in above equation. we get d=1
putting the value of and d we get numbers as
3,5,7,9
wkt sum s= n/2{2(a - 3d)+(n - 1) * 2d}
here
s= 24 and n=4
therefore a= 6
substituting a=6 in above equation. we get d=1
putting the value of and d we get numbers as
3,5,7,9
Answered by
2
Answer:
- the question is missing square of the product of their Extreamest
- the no. are 3,5,7,9
Step-by-step explanation:
See the above pic for reference
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