The sum of how many terms of the A.P. 10, 12., 14, will be 190
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an=190
d=2
n=?
a=10
an=a+(n-1)d
190=10+(n-1)2
t.p
190-10=(n-1)2
180=(n-1)2
180/2=(n-1)
90=(n-1)
t.p
n=90-1
n=89
answer is n=89
I hope this is useful
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