Question

THE SUM OF LCM AND HCFOF TWO NUMBERS IS 1260 AND THEIR LCMIS 900 MORE THAN HCF,FIND THE PRODUCT OF TWO NUMBERS?

Answer 1

Let HCF be x
LCM=900+x
HCF+LCM=x+(900+x)
1260 =2x+900
1260-900=2x
360 =2x
360/2 =x
180 =x
HCF=180 LCM=1080
HCF×LCM =180×1080
= 194400
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Answer 2

HEY FRIEND HERE IS UR ANSWER ,

Given that the sum of HCF and LCM = 1260.

LCM + HCM = 1260  --------------------- (1)

Given that their LCM is 900 more than the HCF.

Let HCF = x.   ------------ (2)

Then the LCM = 900 + x.   ------------------- (3)

On solving (1),(2),(3).

1260 = x + (900 + x)

1260 = x + 900 + x

1260 = 2x + 900

1260 - 900 = 2x

360 = 2x

x = 360/2

x = 180.

Now, we got

HCF = 180.

Then, LCM = 900

                   = 900 + 180

                  = 1080.

                  

We know that product of two numbers = HCF * LCM

                                                                 = 180 * 1080

                                                                 = 194400.

HOPE IT HELPS :)

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