Question

The sum of two digit number and the number reversing its digit is 66. if the digit differs by 2 find the number

Answer 1

Let us assume, x and y are the two digits of the two-digit number and also assume x > y

Therefore, the two-digit number = 10x + y and the reversed number = 10y + x

Given:

10x + y + 10y + x = 66

11x + 11y = 66 

x + y = 6 ---------------1

Also given:

x - y = 2 --------------2

Adding equation 1 and equation 2

2x = 8

x = 4

Therefore, y = x - 2 = 4 - 2 = 2

Therefore, the two-digit number = 10x + y = 10*4 + 2 = 42

Answer - The number is 42