Question

The sum of money at compound interest amounys to thrice itself in 3 years. In how many years will it be 9 times itself.

Answer 1

Answer:

Let the sum be x

⇒ x becomes 3x in 3 years

⇒ x ( 1 + $\frac{R}{100}$ )³ =3x

⇒( 1 + $\frac{R}{100}$ )³ =3x --- (1)

⇒Let x becomes 9x in n years

⇒( 1 + $\frac{R}{100})^n$ =9x

⇒( 1 + $\frac{R}{100})^n$ =9 ---(2)

⇒[(1+ $\frac{R}{100}$ )³]² =3²=9 [From ( 1 )]

⇒(1+ $\frac{R}{100})^6$ = 9 ----- ( 3 )

⇒From ( 2 ) and ( 3 )

⇒ n=6

∴Required number of years are 6.

Answer 2

Answer:

6 YEARS

Step-by-step explanation:

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