Question

the sum of n,2n,3m terms of an ap are s1,s2,s3 proove that s3=(s2-s1) ​

Answer 1

I think ur question is wrong .

I think ur question may be this

The sum of n, 2n ,3n terms of an AP are S1,S2,S3,respectively. Prove that S3 =3(S2- S1)

Solution:Let ‘a’ be the first term of the AP and ‘d’ be the common difference S1 = (n/2)[2a + (n – 1)d] --- (1) S2 = (2n/2)[2a + (2n – 1)d] = n[2a + (n – 1)d] --- (2) S3 = (3n/2)[2a + (3n – 1)d] --- (3) Consider the RHS: 3(S2 – S1)

= S3

= L.H.S ∴ S3 = 3(S2 - S1) .

If my answer is correct

Then vote..,

Answer 2

Answer:

Step-by-step explanation: