The sum of n terms of an ap is 3 and square + 4 and + then the common difference of the ap is
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Answer:
S1 = 3(1) + 2(1)2 = 5 = t1
S2 = 3(2) + 2(2)2 = 14 = t1 + t2
∴ S2 - S1 = 9 = t2
∴ d = t2 - t1 = 9 - 5 = 4
Step-by-step explanation:
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