Math, asked by surman3155, 1 year ago

The sum of n terms of two arithmetic series are in the ratio (7n+1): (4n+27) find the ratio of their 11th terms.

Answers

Answered by Anonymous

4

★ ARITHMETIC PROGRESSION ★

Given , the ratio of sum to n terms of two arithmetic progression :

7n + 1 : 4n + 27

Required :

Ratio of their 11th terms respectively :

7 ( 2n - 1 ) + 1 : 4 ( 2n - 1 ) + 27

HERE : n = 11

Hence ,

147 + 1 : 84 + 27

148 : 111

The above ratio is the required result

★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★

Previous Question

Next Question

Similar questions

English, 8 months ago

what is the irrational number between 2 and root 8 is...

Chemistry, 8 months ago

why is the Earth called the blue planet ...

Chemistry, 8 months ago

A chemical equation containing an unequal number of atoms of reactants and products is called 1)balanced chemical equation 2) unbalanced chemical equation 3) chemical equation choose the option...

Math, 1 year ago

The sum of first m terms of an ap is4m^2-m if its nth term is 107 find the value of n also find its 21st term of the ap...

Math, 1 year ago

The sides of the triangle are in the ratio 13 is to 14 is to 15 and its perimeter is 84 cm what is the area of triangle...

English, 1 year ago

you have noticed that a lot of students litter the premises during school dispersal discuss with your partner.would it be a good idea to .... Asl cbse prompt.

English, 1 year ago

My friend is shy and often face prblm with group task and not able ti give her best and get left out often do you feel she will be open to tell you the reason...

Science, 1 year ago

write the functions of mitochondria...