Three coins are tossed simultaneously find the probalility of getting three heads, exactly 2 heads, at least 2 heads
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sample space=(hhh hth htt hht ttt tth tht thh)
total no of elements in sample space=8
no of elements in which three heads comes =1( hhh)
therefore probability of getting three heads=1÷8
no of events in which 2 heads come=3(hht hth thh)
therefore probability of getting exactly 2 heads =3÷8
at least two heads means event in which 2or more than 2 Head comes,this is possible in 4 events therefore probability of getting at least 2 heads= 4÷8=1÷2
total no of elements in sample space=8
no of elements in which three heads comes =1( hhh)
therefore probability of getting three heads=1÷8
no of events in which 2 heads come=3(hht hth thh)
therefore probability of getting exactly 2 heads =3÷8
at least two heads means event in which 2or more than 2 Head comes,this is possible in 4 events therefore probability of getting at least 2 heads= 4÷8=1÷2
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