The sum of natural no. And its reciprocal is 65/8. Find the natural no. Plzz hlp
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Heya!
Let us find the answer:
Solution:
Let the Number be k,
It's reciprocal is 1/k .
⇒ k + 1/k = 65/8
⇒ k² + 1/k = 65/8
⇒ 8k² + 8 = 65k
⇒ 8k² + 8 - 65k = 0
⇒ 8k² - 64k - k + 8 = 0
⇒ 8k(k - 8) - 1(k - 8) = 0
⇒ 8k - 1(k - 8) = 0
⇒ 8k - 1 = 0
⇒ 8k = 1
⇒ k = 1/8
⇒ k - 8=0
⇒ k = 8
Hence, the number is 8 or 1/8.
Let us find the answer:
Solution:
Let the Number be k,
It's reciprocal is 1/k .
⇒ k + 1/k = 65/8
⇒ k² + 1/k = 65/8
⇒ 8k² + 8 = 65k
⇒ 8k² + 8 - 65k = 0
⇒ 8k² - 64k - k + 8 = 0
⇒ 8k(k - 8) - 1(k - 8) = 0
⇒ 8k - 1(k - 8) = 0
⇒ 8k - 1 = 0
⇒ 8k = 1
⇒ k = 1/8
⇒ k - 8=0
⇒ k = 8
Hence, the number is 8 or 1/8.
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