The sum of q terms of an A.P IS 162.The ratio of the sixth term and the 10th term is 1:2. Find the first and the 15th term of this A.P.
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ratio = (a+5d) / (a+9d) = 1/2
=> a + d = 0 => a = -d
sum of 9 terms = 162
(2a+8d) *9/2 = 162
6d = 36
d = 6 , a = -6
15th term = a + 14 d = 78
1st term = -6
=> a + d = 0 => a = -d
sum of 9 terms = 162
(2a+8d) *9/2 = 162
6d = 36
d = 6 , a = -6
15th term = a + 14 d = 78
1st term = -6
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