The sum of square of two no. is 145. if square root of one no. is 3. then find the other no. .
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Answer:
a2=(a2+b2)+(a2−b2)2
b2=(a2+b2)−(a2−b2)2
⟹a2=145+172=81
⟹b2=145−172=64
⟹a=±9 b=±8
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