Question

the sum of squares of two positive numbers is 232 and one of them is 4 less than thrice The Other find the numbers​

Answer 1

Let one of the numbers be n

then the other number is 3n - 4

So, n^2 + (3n-4)^2 = 232

n^2 + 9n^2 +16 - 24n = 232

11n^2 -24n - 216 = 0

Solve it and you'll find the answer.

Answer 2

See the above ans. I hope it will help you