Question

The sum of the ages of A and B is 46. Five years ago , the age of B was twice that of A. Find A's age

Answer 1

≡QUESTION≡

The sum of the ages of A and B is 46. Five years ago , the age of B was twice that of A. Find A's age.

                                                     

║⊕ANSWER⊕║

5 years ago

Let A's age be x

Age of B = 2x - 5 yrs

A. T. Q. :-

2x - 5 + x= 46

3x - 5 = 46

3x = 46 + 5

x = 51/3

x = 17

∴ A is 17 years old.

                                                         

Answer 2

Answer:

Age of A is 17 years

Step-by-step explanation:

We Have :-

Sum of the ages of A and B is 46

Five years ago , the age of B was twice that of A

To Find :-

A's age

Solution :-

Let the ages be x

x + 2x - 5 = 46

3x = 51

x = 17

Age of A is 17 years