Question

The sum of the ages of a father and son is 45 years. five years ago, the product of their ages was four times the fathers age at that time. the present age of father and son * 1 point

Answer 1

Let the age of father be x years and age of his son be ( 45 - x ) years,






Five years ago,
Age of father = ( x - 5 ) years
Age of his son = ( 45 - x - 5 ) years = ( 40 - x ) years



According to the question,

Product of their ages five years ago = 4 × father's age five years ago


=> ( x - 5 ) ( 40 - x ) = 4( x - 5 )

$= > \cancel{(x - 5)}(40 - x) = 4 \cancel{(x - 5)}$

=> 40 - x = 4

=> 40 - 4 = x

=> 36 = x







Hence,
Present age of father = x years = 36 years

Present age of his son = ( 45 - x ) = ( 45 - 36 ) = 9 years
$\:$

Answer 2

Answer:

The sum of the ages of a father and son is 45 years and 5 years back, the product of their ages was four times the fathers age at that time.

So, the present age of the father is 36 years and present age of son is 9 years.

Step-by-step explanation:

• Let the father's age be x year and son's age be y years.

• Now the sum of the ages of a father and son is 45 years.

• so, we can write:

   x + y  = 45

⇒ x = 45 - y .............................................................................(i)

• 5 years back, father's age was x-5;

• 5 years back, son's age was y-5;

• According to the given problem , 5 years ago, the product of their ages was four times the fathers age at that time.

• so,  (x-5).(y-5) = 4(x-5)

    ⇒ y-5 = 4

    ⇒ y = 4+5

    ⇒ y = 9

• so, the present age of the son is 9 years.

• Putting this value in equation (i) , we will get

  x = 45 - y

⇒ x = 45 - 9

⇒ x = 36

• Hence the present age of the father is 36 years and present age of son is 9 years.