the sum of the ages of a father and son is 45 years. five years ago the product of their ages was 4 times the father's age at that time. the present ages of the father and son, respectively are,
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HEY Buddy......!! here is ur answer
Let the present age of son is 'x' years and Son is 'y' years.
Now, according to the question...
x+y = 45......(1)
Five years ago the age of father = (x-5) years and the age of son = (y-5) years.
Again, according to the question....
(x-5)(y-5) = 4(x-5)
=> (x-5)(45-x-5) = 4(x-5) [ from equation (1) ]
=> (x-5)(40-x) = 4(x-5)
=> 40-x =4
=> x = 36
and from equation (1).....
36+y = 45
=> y = 9
Thus, the present age of father is 36 years and the present age of son is 9 years.
I hope it will be helpful for you......!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
Let the present age of son is 'x' years and Son is 'y' years.
Now, according to the question...
x+y = 45......(1)
Five years ago the age of father = (x-5) years and the age of son = (y-5) years.
Again, according to the question....
(x-5)(y-5) = 4(x-5)
=> (x-5)(45-x-5) = 4(x-5) [ from equation (1) ]
=> (x-5)(40-x) = 4(x-5)
=> 40-x =4
=> x = 36
and from equation (1).....
36+y = 45
=> y = 9
Thus, the present age of father is 36 years and the present age of son is 9 years.
I hope it will be helpful for you......!!
THANK YOU ✌️✌️
MARK IT AS BRAINLIEST
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