The sum of the ages of a son and father is 45 years and yhe product of their age is 126
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Answered by
3
x+y = 45
xy = 126
(45-y)y = 126
45y-y^2 - 126 = 0
y^2-45y+126 = 0
y^2-42y-3y+126= 0
y(y-42) - 3(y-42) = 0
y = 42 or 3
if y = 42 then x will be 3
if y = 3 then x will be 42
so ages will be 42, 3
xy = 126
(45-y)y = 126
45y-y^2 - 126 = 0
y^2-45y+126 = 0
y^2-42y-3y+126= 0
y(y-42) - 3(y-42) = 0
y = 42 or 3
if y = 42 then x will be 3
if y = 3 then x will be 42
so ages will be 42, 3
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0
Answer:
age of father is 42 and son is 3
Step-by-step explanation:
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