Question

The sum of the base angle of a triangle is 140 and their difference is 40. The angles of triangle are

Answer 1

Answer:∠A= 90° , ∠B= 50° , ∠C =40°

Step-by-step explanation:

Let angles of triangles be A,B &C

Let base angles be ∠A and ∠B

As we know,

∠A + ∠B + ∠C = 180°

From the given condition,

∠A + ∠B= 140°

also, ∠A -∠B=40°.

∴∠A = 40 + ∠B.

∠A + ∠B + ∠C = 180°

∴ 140 + ∠C =180°

∠C = 40°

∠A + ∠B + ∠C = 180°

(40 + ∠B )+ ∠B + 40° = 180°

2∠B + 80° = 180°

∠B = 50°

∠A + ∠B + ∠C = 180°

∠A + 50° + 40° = 180°

∠A = 90°