Question

the sum of the digit of a 2 digit number is 6 the number obtained by interchanging its digits is 18 more than the original number find the original number

Answer 1

Let Ten’s digit=x=x

Therefore, One’s digit=6−x=6−x

No.=10(x)+1(6−x)No.=10(x)+1(6−x)

=10x+6−x=10x+6−x

=9x+6=9x+6

Interchanged no=10(6−x)+x=10(6−x)+x

=−10x+60+x=−10x+60+x

=60–9x=60–9x

From the question::

9x+6+18=60–9x9x+6+18=60–9x

18x=3618x=36

x=2x=2

The no. is=24 please mark me brsinliedt