The sum of the digit of a two digit number is 12 if the new number formed by reversing the digit is greater than the original number by 54 find the number
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Step-by-step explanation:
Let First no be x
and second no be (x- 12)
Then no= 1X x + 10 (12- x)
= x + 120- 10x
= 120-9x
on resving the digit
new no = 10x + 1 (12-x)
= 10x + 12- x
= 9x +12
A/q 9x +12 = 120 - 9x + 54
9x + 12 = 174 -9x
9x + 9x = 174
18x = 174
x = 174 / 18
x=
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