Question

the sum of the digit of a two digit number is 6 the number obtained by interchanging its digit is 18 more than the original number find the original number

Answer 1

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Answer 2

Solution :-

Let the tens and units digits of the required number be a and b respectively.

Then,

a + b = 6 ... ( 1 )

Original number = 10a + b

Number obtained by interchanging its digits =

10b + a

→ ( 10b + a ) - ( 10a + b ) = 18

→ 9 ( b - a )

→ b - a = 2 ... ( 2 )

Adding (i) and (ii), we get : 2b = 8 → b = 4

Putting b = 4 in (i), we get : a + 4 = 6 → a = 2

the original number = ( 10a + b ) = ( 10 × 2 +4 ) = 24

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