Question

the sum of the digit of a two digit number is 9 on reversing the digit the new number is obtained is 45 more than the original number find the number

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Hey mate here is your answer ::::

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Let the digit at one's place be X
Let the digit at ten's place be 9-X

No . formed = 10(9-X)+X
.........................= 90-10X+X
.........................= 90-9X


No. formed on reversing the digits = 10(X)+9-X
.................................................................... = 10X+9-X
.................................................................... = 9X+9

ORIGINAL NUMBER ::::

=90-9x+45=9x+9
=135-9x=9x+9
=-9x-9x=9-135
=-18x=-126
=X=-126/-18
=X=7

Therefore, the digit at one's place = X = 7
....................., the digit at ten's place = X = 9-X = 2

Hence , Original Number is ****27******

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Hope it helps you Mate ☺️☺️☺️

♥❤️ Shreya Verma