the sum of the digits in a two - digits number is 9. the number obtained by interchanging the digits exceeds tge original number by 27. find the two - digit number.
Answers
Answered by
2
let the digits be xy
then x+y=9
and the number =10x+y
according to question
when digits interchanged it exceeds the number by 27
tgerefore 10y+x=27+10x+y
9y-9x=27
taking 9 common
y-x=3
and other equatin was x+y=9
solve both equations 2y=12
so y=6 and x =3
therfore required no =36..
then x+y=9
and the number =10x+y
according to question
when digits interchanged it exceeds the number by 27
tgerefore 10y+x=27+10x+y
9y-9x=27
taking 9 common
y-x=3
and other equatin was x+y=9
solve both equations 2y=12
so y=6 and x =3
therfore required no =36..
Similar questions