Math, asked by neha6063, 1 year ago

the sum of the digits of a two-digit is 15. If the number formed by reversing the digits is less than the original number by 27 ,find the original number.

Answers

Answered by inhumandrowsey

Let the number with two digits be 10 x + y

Sum of the digits is 15

x + y = 15 ----------------- (1)

Number formed by reversing 10 y+x

10x+y=10y+x+27

9x-9y=27

x - y = 3 ------------------- (2)

x = 15 - y putting in equation 2

15 - y - y = 3

2y = 12

y = 6

x + y = 15

x + 6 = 16

x = 9

So the number is 10 x + y

10 (9) + 6 = 90 + 6 = 96

QUESTION 2

The sum of two numbers is 2490. if 6.5% of one number is equal to 8.5% of the other find the numbers.

Let the numbers be x and y

6.5% of x = 8.5% of y

6.5/100 x = 8.5/100 y

13 x = 17 y

x/y = 17/13

we have to split the number 2490 in the ratio of 17:13 and we will get our number

so 17/30 * 2490 = 1411

So one of the number is 1411

another is 2490 - 1411 = 1079

inhumandrowsey: sure

inhumandrowsey: post

neha6063: the sum of two numbers is 2490. if 6.5% of one number is equal to 8.5% of the other find the numbers.

inhumandrowsey: Let the numbers be x and y

neha6063: then

inhumandrowsey: you can look in the above solution, i have edited and solved at the bottom

neha6063: thank u so much

inhumandrowsey: no problem

inhumandrowsey: you can ask any question you want

neha6063: okay

Answered by mdarifalhasann

X+y=15 , then 10x+y _ 10y_ x= 27
X_y =3

So by calculating number is 69

Previous Question

Next Question