Question

the sum of the digits of a two digit no is 15 . if the no. formed by reversing the digits ís less than the original no. by 27, then find the original no. ques no. 20 of quespaper of annual exam of class 8 of 2018​

Answer 1

let tens digit of the original number be x

let tens digit of the original number be xso original number,

let tens digit of the original number be xso original number,10(x) + (15-x)

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + x

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore[10(x) + (15-x)]-[10(15-x)+x] = 27

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore[10(x) + (15-x)]-[10(15-x)+x] = 27or 10x + 15-x - 150+10x-x = 27

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore[10(x) + (15-x)]-[10(15-x)+x] = 27or 10x + 15-x - 150+10x-x = 27or 10x + 10x + 15 - 150 -x - x = 27

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore[10(x) + (15-x)]-[10(15-x)+x] = 27or 10x + 15-x - 150+10x-x = 27or 10x + 10x + 15 - 150 -x - x = 27or 20x - 135 -2x = 27

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore[10(x) + (15-x)]-[10(15-x)+x] = 27or 10x + 15-x - 150+10x-x = 27or 10x + 10x + 15 - 150 -x - x = 27or 20x - 135 -2x = 27or 18x - 135 = 27

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore[10(x) + (15-x)]-[10(15-x)+x] = 27or 10x + 15-x - 150+10x-x = 27or 10x + 10x + 15 - 150 -x - x = 27or 20x - 135 -2x = 27or 18x - 135 = 27or 18x = 27 + 135

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore[10(x) + (15-x)]-[10(15-x)+x] = 27or 10x + 15-x - 150+10x-x = 27or 10x + 10x + 15 - 150 -x - x = 27or 20x - 135 -2x = 27or 18x - 135 = 27or 18x = 27 + 135or 18x = 162

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore[10(x) + (15-x)]-[10(15-x)+x] = 27or 10x + 15-x - 150+10x-x = 27or 10x + 10x + 15 - 150 -x - x = 27or 20x - 135 -2x = 27or 18x - 135 = 27or 18x = 27 + 135or 18x = 162or x = 162/18

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore[10(x) + (15-x)]-[10(15-x)+x] = 27or 10x + 15-x - 150+10x-x = 27or 10x + 10x + 15 - 150 -x - x = 27or 20x - 135 -2x = 27or 18x - 135 = 27or 18x = 27 + 135or 18x = 162or x = 162/18or x = 9

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore[10(x) + (15-x)]-[10(15-x)+x] = 27or 10x + 15-x - 150+10x-x = 27or 10x + 10x + 15 - 150 -x - x = 27or 20x - 135 -2x = 27or 18x - 135 = 27or 18x = 27 + 135or 18x = 162or x = 162/18or x = 9original number = 10(x) + (15-x)

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore[10(x) + (15-x)]-[10(15-x)+x] = 27or 10x + 15-x - 150+10x-x = 27or 10x + 10x + 15 - 150 -x - x = 27or 20x - 135 -2x = 27or 18x - 135 = 27or 18x = 27 + 135or 18x = 162or x = 162/18or x = 9original number = 10(x) + (15-x) = 10(9) + (15-9)

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore[10(x) + (15-x)]-[10(15-x)+x] = 27or 10x + 15-x - 150+10x-x = 27or 10x + 10x + 15 - 150 -x - x = 27or 20x - 135 -2x = 27or 18x - 135 = 27or 18x = 27 + 135or 18x = 162or x = 162/18or x = 9original number = 10(x) + (15-x) = 10(9) + (15-9) = 90+6

let tens digit of the original number be xso original number,10(x) + (15-x) reversing digits mean10(15-x) + xtherefore[10(x) + (15-x)]-[10(15-x)+x] = 27or 10x + 15-x - 150+10x-x = 27or 10x + 10x + 15 - 150 -x - x = 27or 20x - 135 -2x = 27or 18x - 135 = 27or 18x = 27 + 135or 18x = 162or x = 162/18or x = 9original number = 10(x) + (15-x) = 10(9) + (15-9) = 90+6 = 96

Hope it help...

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