Question

The sum of the digits of a two digit number is 10 . Of the number formed by reversing the digit is greater than the original number by 18 find the original number

Answer 1

Solution :- Let the ones digit be x
and ten's place digit be (10-x)
Original number = x + 10(10 - x )
= x + 100 - 10x
= 100 - 9x
On reversing, One's place digit = (10 - x)
Ten's place digit = x
New number = 10 - x + 10(x)
= 10 - x + 10x
= 10 + 9x
A/Q
10 + 9x - (100 - 9x) = 18
10 + 9x - 100 + 9x = 18
18x - 90 = 18
18x = 18 + 90
18x = 108
x = 108/18
x = 6

Original number = 100 - 9x
= 100 - 9×6
= 100 - 54
= 46 AnSWer

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