Question

The sum of the digits of a
two - digit number is 11. The
number got by interchanging
the digit is 27 more than
the original number what
is the number?​

Answer 1

Answer:

Step-by-step explanation:

Let the number be x and the number at tens place be 11-x

Now 10 (11-x)+1×x

110-9x

Now when digits are interchanged

10x+11-x

9x+11

9x+11-110+9x=27

18x=126

X=7

So orginal no was 47

Answer 2

Let the digits of that two digit number be x and y

According to the given question.

x + y = 11 ... Equation ( i )

This two digit number can be written like this 10x + y

When we interchange the digits the new number becomes 10y + x

According to the given address question

10y + x = 27 + 10x + y

9y - 9x = 27

y - x = 3 ... Equation ii

Now, Add both the Equations we have

2y = 14

y = 7

Put value of y in Equation i we have

x + 7 = 11

x = 4

So, the two digit number is 47