the sum of the digits of a two-digit number is 13 if the number obtained by reversing the digits is 45 more than the original number find the original number
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Let the one number be x
And another be y
ATQ
x+y=13.................1
And now ATQ original no. Will be 10x+y and no.obtained by reversing the digits is 10y+x
ATQ
10y+x=45+10x+y..........2
Solving equations 1 and 2 by elimination method
We get x=4 and y=9
So the original no. Is 49 ans..
Cheers
And another be y
ATQ
x+y=13.................1
And now ATQ original no. Will be 10x+y and no.obtained by reversing the digits is 10y+x
ATQ
10y+x=45+10x+y..........2
Solving equations 1 and 2 by elimination method
We get x=4 and y=9
So the original no. Is 49 ans..
Cheers
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