The sum of the digits of a two digit number is 15. If the number formed by reversing the digits is less than the original number by 27 thenn find the original number
Answers
Original Number = 96
Step-by-step explanation:
Given:
- Sum of digits of two digit number is 15.
- Reversed number is 27 less than original.
To Find:
- What is the original number ?
Solution: Let the tens digit be x and ones digit be y. Therefore original number is 10x + y.
Tens + ones = 15
x + y = 15
x = (15 – y)......1
[ Now reversing the digits new number formed will be ]
- Reversed number = 10y + x
A/q
Reversed number is 27 less than original number.
10x + y – 27 = 10y + x
10x – x – 27 = 10y – y
9x – 27 = 9y
9(x – 3) = 9y
x – 3 = 9y/9
15 – y – 3 = y
12 = y + y
12 = 2y
6 = y
So the digits of number is
Ones digit is y = 6
Tens digit is x = 15 – 6 = 9
∴ Number is 10(9) + 6 = 90 + 6 = 96
⚘ Given :-
- The sum of the digits of a two digit number is 15.
- The number formed by reversing the digits is less than the original number by 27.
⚘ To Find :-
- The Original Number.
⚘ Solution :-
Let,
Ones Digit be x.
Tens Digit be y.
So, Original Number = 10x + y.
Now, It is Given,
➛x + y = 15.
➛x = 15 - y.
Now, Reversed Number = 10y + x.
According To The Question, The Equation :-
➛10x + y - 27 = 10y + x.
➛10x - x - y - 10y = 27.
➛9x - 27 = 9y.
➛9(x - 3) = 9y.
➛x - 3 = 9y/9.
➛x - 3 = y.
➛15 - y - 3 = y
➛2y = 12.
➛y = 6.
So,
- Ten's Digit = x = 6.
- One's Digit = 15 - y = 9.