Question

The sum of the digits of a two digit number is 5.
If the digits are reversed, the number is reduced
by 27. Find the number.
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Answer 1

Answer:

Let the units digit be x.

The tens digit =5−x

Original number =10(5−x)+x=50−9x

If digits are reversed, number is reduced by 27.

50−9x−27=10x+5−x

23−9x=9x+5

18x=18

∴x=1

Tens place =5−1=4

Therefore, the number is 41.