the sum of the digits of a two digit number is 5 on adding 27 to the number its digits are reversed find the original number
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Given: The sum of the digits of a two digit number is 5, on adding 27 to the number its digits are reversed.
To find: The original number.
Solution:
- Now we have given that The sum of the digits of a two digit number is 5.
- So, let the number be 10x + y. Then:
x + y = 5
x = 5 - y ......(i)
- Now It is given that on adding 27 to the number its digits are reversed.
10x + y + 27 = 10y + x
9x - 9y + 27 = 0
- Now putting (i), in above equation, we get:
9(5 - y) - 9y + 27 = 0
45 - 9y - 9y + 27 = 0
72 = 18y
y = 72 / 18
y = 4
- Now putting y = 4 in equation (i), we get:
x = 5 - y
x = 5 - 4
x = 1
- So the number is:
10x + y = 10(1) + 4 = 14
Answer:
Therefore the number is 14.
Answer:
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Step-by-step explanation:
step by step explanation answer is 14 ok.....
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