The sum of the digits of a two digit number is 5. On adding 27 to the number its digits are reversed .Find the original number
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let x and y
x+y=5 ........ (1)
after adding 27
10x+y+27=10y+x
10x-x-10y+y+27=0
9x-9y+27=0
x-y+3=0...... (2)
by elimination method
x+y=5
x-y=-3
2x=2
x=1 put in (1) equation
x+y=5
y=5-1
y=4
so the no. are 1 and 4 hope this will help you and please mark as a brainlist answer
x+y=5 ........ (1)
after adding 27
10x+y+27=10y+x
10x-x-10y+y+27=0
9x-9y+27=0
x-y+3=0...... (2)
by elimination method
x+y=5
x-y=-3
2x=2
x=1 put in (1) equation
x+y=5
y=5-1
y=4
so the no. are 1 and 4 hope this will help you and please mark as a brainlist answer
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