the sum of the digits of a two digit number is 7 the number obtained by interchanging the digits exceeds the original number by 7 find the number
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I think it is 70 ......
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Answer:
Let the first digit number be x
tens digit number y
10y + x = 7 ....... 1
Interchange digit
10x + y = 10y + x +7
10x - x + y - 10y = 7
9x - 9y = 7 ....... 2
Add equation no. 1 and 2
9(x + 10y = 7)
10(9x - 9y = 7)
9x +90y = 63
90x - 90y = 70
= 99x = 133
x = 133 / 99
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