the sum of the digits of a two digit number is 9 the number is 6 times the unitd digit.find the number
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Answered by
5
Let the unit place be x
The tens place be y
ATP
x+y=9.........i
10y+x=6x.....ii
Now finding the value of x from i
x+y=9
x=9-y
Now Substituting value of x in ii
10y+x=6x
10y+9-y=6(9-y)
9y+9=54-6y
9y+6y=54-9
15y=45
y=45/15
y=3
Now putting the value of y in i
x+y=9
x+3=9
x=9-3
x=6
Now the no. Is
10y+x
10.3+6
36
HOPE U MIGHT FIND MY ANSWER USEFUL
The tens place be y
ATP
x+y=9.........i
10y+x=6x.....ii
Now finding the value of x from i
x+y=9
x=9-y
Now Substituting value of x in ii
10y+x=6x
10y+9-y=6(9-y)
9y+9=54-6y
9y+6y=54-9
15y=45
y=45/15
y=3
Now putting the value of y in i
x+y=9
x+3=9
x=9-3
x=6
Now the no. Is
10y+x
10.3+6
36
HOPE U MIGHT FIND MY ANSWER USEFUL
Answered by
1
the required number is 36
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