Question

the sum of the digits of a two -digits numbers is 15 if the number obtain by reversing the digits is less than the original number by 27 find the original number ​

Answer 1

Step-by-step explanation:

Let the two digits number be xy in which ten's digit is x and one's digit is y.

Sum of two digit number =15

The original number=xy= 10x+y

A/Q,

x+y=15 -----------(1)

On reversing the digits

yx=10y+x

A/Q,

10y+x=(10x+y)–27

10y+x-10x-y= –27

9y–9x= –27

–(9y+9x) = –(–27)

9x-9y=27

x-y=3————(2) (divided by 3 on both sides)

On adding equations (1) and (2), we get

x+y+x-y=15+3

2x=18

x=9

By putting the value of 'x' in equation (2), we get

x-y=3

9-y=3

-y= -6

y=6

Hence, the original number is (10x+y) =(10×9+6) =96

Answer 2

Answer:

Heya mate Here's your question mate Follow me