Question

the sum of the digits of two digit is 11. when a digit are reversed then the number is 9. find the original number

Answer 1

hiiii
let tens place digit = x
let unit place digit = y
the number = 10 x+y
reversed value
=10 y+x
given
10 x+y-(10 y+x)= 9
9 x-9 y= 9
dividing each term with 9 we get
x-y =1.......i
given = x+y = 11.......ii
adding i and ii
2x=12
x=6
put x = 6 in ii
y = 11-6
y = 5
the number = 10 * 6 +6
= 65 answer...
hope it help u 
plzz mark as brainlist

Answer 2

Let the digits be x and y
x+y=11
Let the no be 10x+y
When the digits interchange the no become
10y+x
Hope u can continue after that