the sum of the first 7 terms of an AP is 63 and sum of next 7 terms is 161
Answers
Answered by
8
Answer:
a=3 and d=2
Step-by-step explanation:
S7=63
S14-S7=161
S14=161+63=224
Sn = n/2(2a+(n-1)d)
S7=7/2(2a+6d)=63
S14= 7(2a+13d)=224
2a+6d=18.....1
2a+13d=32.....2
subtracting eq1 and 2
7d=14
d=2....3
substituting 3 in eq1
2a=18-12=6
a=3
required AP = 3,5,7,9..
hope it helps u
mark as brainliest
Similar questions