Question

the sum of the first n terms of an ApP is 3n2+6n find the nth term of this AP

Answer 1

Let the sum of first n terms of the A.P.=Sn

▶Given: Sn = 3n2 – 4n  ....(i)

 Now...
Replacing n by (n –1) in (i), we get,

Sn – 1 = 3(n – 1)2 – 4(n – 1)

nth term of the A.P. an = Sn – Sn – 1


 ∴ an = (3n2 – 4n) – [3(n – 1)2 – 4(n – 1)]

⇒ an = 3 [ n2 – (n – 1)2] – 4 [n – (n – 1)]

⇒ an = 3 (n2 – n2 + 2n – 1) – 4 (n – n + 1)

⇒ an = 3(2n –1) – 4

⇒ an = 6n – 3 – 4 

⇒ an= 6n – 7

▶Thus, the nth term of the A.P = (6n – 7) Ans...✔