Question

the sum of the interior angles of a polygon is three times the sum of its exterior angle .determine the number of sides of the polygon

Answer 1

Sum of interior angles
= (2n– 4) × 900
Now, Sum of interior angles of a polygon
= 3(Sum of interior angles)     
(2n – 4) 90 = 3× 360
(2n – 4) = 3 × 4
2n – 4 = 12
2n= 16 
 n = 8

Number of sides of the polygon = 8

hope it helps

Answer 2

Answer: 8 sides

Step-by-step explanation:

Sum of interior angles

= (2n– 4) × 900

Now, Sum of interior angles of a polygon

= 3(Sum of interior angles)      

(2n – 4) 90 = 3× 360

(2n – 4) = 3 × 4

2n – 4 = 12

2n= 16  

n = 8

Number of sides of the polygon = 8

hope it helps

Avya