Question

The sum of the lengths of the bases of a trapezium whose altitude is 24 m and whose area is 144 m2 is

Answer 1

Answer:

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Step-by-step explanation:

Area of trapezium =2a+b×h

Where, a and b are parallel sides and h is perpendicular height.

So, (a+b) is sum of length of bases of a trapezium.

Now,

Area of trapezium =2a+b×h

⇒  4.2×1002=2a+b×280       {1m=100cm}

⇒  2808.4×10000=a+b

⇒  a+b=300cm

Answer 2

Answer:

Area of trapezium =

2

a+b

×h

Where, a and b are parallel sides and h is perpendicular height.

So, (a+b) is sum of length of bases of a trapezium.

Now,

Area of trapezium =

2

a+b8

×h

⇒ 4.2×100

2

=

2

a+b

×280 {1m=100cm}

⇒

280

8.4

×10000=a+b

⇒ a+b=300cm

Step-by-step explanation:

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