Question

The sum of the square root of sixteen and the product of four and the cube root of eight

Answer 1

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$\implies \sqrt{16} + 4 + \sqrt[3]{8} \\ \\ = 4 + 4 + 2 \\ (since \: \sqrt{16} = 4 \: and \: \sqrt[3]{8} = 2) \\ \\ = 8 + 2 \\ \\ = 10.$

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